Solution:
Volume =1 Metre X 1 Metre X 0.15 Metre
Volume=0.15 Metre
Or, Dry Volume = 0.15 Cubic Metre
Wet Volume=Dry Volume X 1.54
Wet Volume=0.15 Cubic Metre X 1.54
Wet Volume=0.231 Cubic Metre
Mortar Ratio=1:2:4 (Given)
Sum of Ratios=1+2+4=7
Cement Required=1÷7 X 0.231 CUM
Cement Required=0.033 CUM
Cement Required=0.033 X 28.8
Cement Required=0.95 Bags
Remember 28.8 Bags of Cement Are Required in 1 Cum
Sand Required=2÷7 X 0.231 CUM
Sand Required=0.066 CUM
Aggregates Required=4÷7 X 0.231 CUM
Aggregates Required=0.132 CUM
Steel
Assume 1% of Dry Volume is The Volume of Steel Required
Volume= 1÷100 X 0.231
Volume=0.00231 Cubic Metre
Density=Mass÷Volume
Mass=Density X Volume
Mass=7850 Kg/M3 X 0.00231 M3
Mass=18.13 Kgs
Steel =18.13 Kgs
Binding Wire
Remember 100 Kgs of Steel Requires 1 Kg of Binding Wire
Binding Wire= 1÷100 X 18.13
Binding Wire=0.18 Kgs
Volume =1 Metre X 1 Metre X 0.15 Metre
Volume=0.15 Metre
Or, Dry Volume = 0.15 Cubic Metre
Wet Volume=Dry Volume X 1.54
Wet Volume=0.15 Cubic Metre X 1.54
Wet Volume=0.231 Cubic Metre
Mortar Ratio=1:2:4 (Given)
Sum of Ratios=1+2+4=7
Cement Required=1÷7 X 0.231 CUM
Cement Required=0.033 CUM
Cement Required=0.033 X 28.8
Cement Required=0.95 Bags
Remember 28.8 Bags of Cement Are Required in 1 Cum
Sand Required=2÷7 X 0.231 CUM
Sand Required=0.066 CUM
Aggregates Required=4÷7 X 0.231 CUM
Aggregates Required=0.132 CUM
Steel
Assume 1% of Dry Volume is The Volume of Steel Required
Volume= 1÷100 X 0.231
Volume=0.00231 Cubic Metre
Density=Mass÷Volume
Mass=Density X Volume
Mass=7850 Kg/M3 X 0.00231 M3
Mass=18.13 Kgs
Steel =18.13 Kgs
Binding Wire
Remember 100 Kgs of Steel Requires 1 Kg of Binding Wire
Binding Wire= 1÷100 X 18.13
Binding Wire=0.18 Kgs
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