ANALYSE AN RCC SLAB FOR A ROOM MEASURING 1 METRE X 1 METRE HAVING SLAB THICKNESS EQUAL TO 0.15 METRE

Solution:

Volume =1 Metre X 1 Metre X 0.15 Metre

Volume=0.15 Metre

Or, Dry Volume = 0.15 Cubic Metre

Wet Volume=Dry Volume X 1.54

Wet Volume=0.15 Cubic Metre X 1.54

Wet Volume=0.231 Cubic Metre

Mortar Ratio=1:2:4 (Given)

Sum of Ratios=1+2+4=7

Cement Required=1÷7 X 0.231 CUM

Cement Required=0.033 CUM

Cement Required=0.033 X 28.8

Cement Required=0.95 Bags

Remember 28.8 Bags of Cement Are Required in 1 Cum

Sand Required=2÷7 X 0.231 CUM

Sand Required=0.066 CUM


Aggregates Required=4÷7 X 0.231 CUM

Aggregates Required=0.132 CUM

Steel

Assume 1% of  Dry Volume is The Volume of Steel Required

Volume= 1÷100 X 0.231

Volume=0.00231 Cubic Metre

Density=Mass÷Volume

Mass=Density X Volume

Mass=7850 Kg/MX  0.00231 M3

Mass=18.13 Kgs

Steel =18.13 Kgs

Binding Wire

Remember 100 Kgs of Steel Requires 1 Kg of Binding Wire

Binding Wire= 1÷100 X 18.13

Binding Wire=0.18 Kgs



















HOW TO ANALYSE 1 CUM OF BRICK MASONARY IN THE RATIO OF 1:6

Solution:

Given Quantity=1 CUM

Mortar Ratio:1:6

Remember 30% Cement Mortar is Required In Case of Stone Masonary

Motar Required= 30% of 1 CUM

Motar Required= 0.3 X 1 CUM

Motar Required=0.3 CUM

Mortar Ratio=1:6 (Given)

Sum of Ratios=1+6=7

Cement Required=1÷7 X 0.3 CUM

Cement Required=0.043 CUM

Cement Required=0.043 X 28.8

Cement Required=1.24 Bags

Remember 28.8 Bags of Cement Are Required in 1 Cum

Sand Required=6÷7 X 0.3 CUM

Sand Required=0.26 CUM

Labour Productivity

1 Mason,1 Men Mazdoor & 1 Women Mazdoor Can Do 1.25 CUM of Brick Masonary Work Per Day

Labour Statement

Mason Required=0.8 No.

Men Mazdoor=0.8 No.

Women Mazdoor=0.8 No.






HOW TO ANALYSE 1 CUM OF STONE MASONARY IN THE RATIO OF 1:6

Solution:

Given Quantity=1 CUM

Mortar Ratio:1:6

Remember 50% Provision is Provided For Stone Dressing/Voids

50% of 1 Cum=0.5 Cum

Total quantity=1Cum+0.5 CUM

Total Quantity=1.5 CUM

In Case of Stone Masonary 40% Cement Mortar is Required.

Motar Required= 40% of 1 CUM

Motar Required= 0.4 X 1 CUM

Motar Required=0.4 CUM

Mortar Ratio=1:6 (Given)

Sum of Ratios=1+6=7

Cement Required=1÷7 X 0.4 CUM

Cement Required=0.057 CUM

Cement Required=0.057 X 28.8

Cement Required=1.64 Bags

Remember 28.8 Bags of Cement Are Required in 1 Cum

Sand Required=6÷7 X 0.4 CUM

Sand Required=0.343 CUM

Labour Productivity

1 Mason,1 Men Mazdoor & 1 Women Mazdoor Can Do 1 CUM of Brick Masonary Work Per Day

1 Stone Dresser Can Dress 1 Cum of Stone Work Per Day

Labour Statement

Mason Required=1 No.

Men Mazdoor=1 No.

Women Mazdoor=1 No.

Stone Dresser=1.5 No.




How Do I Calculate The Capacity of A Water in Circular Tank | How To Calculate Capacity of Water In A Circular Tank



Suppose We Have A Circular Tank Having

Diameter=D Feet

Radius=r Feet

Height=H Feet

Area of Circular Tank
                                           = xD2
                                                4 

or, Area of Circular Tank
                                            = r2
                                                
Volume of Circular Tank=Area Of Circular Tank X Height Of Circular Tank

                                          = r2xH

Capacity of Circular Water Tank=Volume Of Circular Tank (In Cft) X 28.32

Remember 1 Cft of  Water Contains 28.32 Litres Of Water In It.

Example

Calculate The Capacity of Circular Water Tank Having
Diameter=8 Feet
Radius=4 Feet
Height=6 Feet

Solution:

We Know


Area of Circular Tank
                                                = r2
                                                =3.14x4Feetx4Feet
                                                =50.42 Sft

Volume of Circular Tank=Area of Circular Tank X Height Of Circular Tank

                                              = r2xH
                                              =50.42 Sft X 6Feet
                                              =302.52 Cft

Capacity of Circular Water Tank=Volume Of Circular Tank (In Cft) X 28.32
                                                           =302.52x28.32
                                                           =8567.3664 Litres
                                                           =8568 Litres

How Do I Calculate The Water Capacity In A Rectangular Tank|What Is The Formula To Calculate The Capacity Of Water Tanks.


Sol:

Suppose we have a rectangular water tank having dimensions 

Length=A metre Width=B metre & Depth=C metre

Volume=LengthxWidthxDepth

            =A metreXB metreXDepthXC metre

             =ABC Cum

or

Volume=ABCX35.13 Cft

            =abc Cft

Capacity=Volumex28.32

Remember 1 Cft of water contains 28.32 Litres of water in it.

The Product of Volume and Constant Term 28.32 Will Give You The Capacity of Water in A Tank.

Let Us Take An Example

Suppose we want to calculate the capacity of water tank having dimensions


Length=2 Metre,Width=1 Metre,Depth=3 Metre

Volume=2 Metre x 1Metre x 3Metre

Volume=6Cubic Metre(Cum)

Or,

Volume =6 Cum

Now Calculate the Volume in terms of Cubic Feet(Cft)

We Know,

1 Cum=35.31Cft

Volume=6x35.31Cft

Volume=211.86 Cft

In Order to calculate the capacity of water  we have to multiply the volume by 28.32

Therefore,

Capacity of water Tank=Volume of tankx28.32

Remember 1 Cft of water contains 28.32 Litres of water in it

Capacity of water Tank  =211.86x28.32
                                      = 5999.8752 Litres
                                      =6000 Litres (Approx)

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ANALYSE AN RCC SLAB FOR A ROOM MEASURING 1 METRE X 1 METRE HAVING SLAB THICKNESS EQUAL TO 0.15 METRE

Solution: Volume =1 Metre X 1 Metre X 0.15 Metre Volume=0.15 Metre Or, Dry Volume = 0.15 Cubic Metre Wet Volume=Dry Volume X 1.54 ...